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linux 多线程编程初试

2013年06月20日

[目录]

用正确的工具，做正确的事情

基于多线程实现的经典的“生产值-消费者”模型，假设生产缓冲区为1，详细实现如下：

#include <stdlib.h>
#include <stdio.h>
#include <pthread.h>

int product = 0;
pthread_cond_t buf_ready = PTHREAD_COND_INITIALIZER;
pthread_cond_t prod_ready = PTHREAD_COND_INITIALIZER;
pthread_mutex_t prod_lock = PTHREAD_MUTEX_INITIALIZER;

void *producer(void *apue) {
    printf("start producer!\n");
    while(1) {
        pthread_mutex_lock(&prod_lock);
        if(1 == product)
            pthread_cond_wait(&buf_ready, &prod_lock);
        product = 1;
        sleep(1);
        printf("put a product!\n");
        pthread_cond_signal(&prod_ready);
        pthread_mutex_unlock(&prod_lock);
    }
}

void *consumer(void *apue) {
    printf("start consumer!\n");
    while(1) {
        pthread_mutex_lock(&prod_lock);
        if(0 == product)
            pthread_cond_wait(&prod_ready, &prod_lock);
        product = 0;
        sleep(1);
        printf("get a product!\n");
        pthread_cond_signal(&buf_ready);
        pthread_mutex_unlock(&prod_lock);
    }
}

int 
main(void) {
    pthread_t producer_tid, consumer_tid;
    void *tret;
    int err;
    
    pthread_create(&producer_tid, NULL, producer, NULL);
    pthread_create(&consumer_tid, NULL, consumer, NULL);
    pthread_join(producer_tid, &tret);
    pthread_join(consumer_tid, &tret);
    return 0;
}

玩的开心 !!!